A body is released from the top of a tower ' H ' metre high. It takes t second to reach the ground. The height of the body t/2 second after release is (a) H/2 metre from ground (b) H/4 metre from ground (c) 3H/4 metre from ground (d) H/6 metre from ground

Answer: (c). Free fall from rest: h ∝ t². Fallen in t/2: H/4 Height above ground = H - H/4 = 3H/4 So the answer is (c) 3H/4 metre from ground.

A body is released from the top of a tower ' H ' metre high. It takes… | MHT CET 2023 (10 May, Shift 1)

Q14MHT CET 2023 · 10 MAY · SHIFT 1Easy

Motion Under Gravity

A body is released from the top of a tower ' $H$ ' metre high. It takes $t$ second to reach the ground. The height of the body $\frac{t}{2}$ second after release is

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Answer: (c)

Free fall from rest: $h \propto t^2$ .
Fallen in $\frac{t}{2}$ : $\frac{H}{4}$
Height above ground $= H - \frac{H}{4} = \frac{3H}{4}$
So the answer is (c) $\frac{3H}{4}$ metre from ground.

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