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MHT CET 2025 (21 Apr, Shift 2) · Rotational Kinetic Energy, Work & Power

Rotational Kinetic Energy, Work & Power question from MHT CET 2025 (21 Apr, Shift 2)

Q13MHT CET 2025 · 21 APR · SHIFT 2Easy

Rotational Kinetic Energy, Work & Power

A body is rotating about its own axis. Its rotational kinetic energy is ' x ' and its angular momentum is ' yy '. Hence its moment of inertia about its own axis is

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Answer: (b)

  1. K=L22IK = \frac{L^2}{2I}, with K=xK = x and L=yL = y.
  2. I=L22K=y22xI = \frac{L^2}{2K} = \frac{y^2}{2x}
  3. So the answer is (b) y22x\frac{y^2}{2x}.
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