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MHT CET 2026 (20 Apr, Shift 1) · Rotational Kinetic Energy, Work & Power

Rotational Kinetic Energy, Work & Power question from MHT CET 2026 (20 Apr, Shift 1)

Q1MHT CET 2026 · 20 APR · SHIFT 1Easy

Rotational Kinetic Energy, Work & Power

A body is rotating about its own axis. Its rotational kinetic energy is ' $x$ ' and its angular momentum is ' $y$ '. Hence its moment of inertia about its own axis is

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Answer: (d)

$K = \frac{L^2}{2I}$ , with $K = x$ and $L = y$ .
$I = \frac{L^2}{2K} = \frac{y^2}{2x}$
So the answer is (d) $\frac{y^2}{2x}$ .

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