A body moves a distance of 10 m along a straight line under the action of a 5 N force. If the work done is 25 J, then angle between the force and direction of motion of the body is (a) 60° (b) 75° (c) 30° (d) 45°

Answer: (a). W = Fscos θ ⇒ 25 = 5 × 10 cos θ cos θ = 1/2 ⇒ θ = 60° So the answer is (a) 60°.

A body moves a distance of 10 m along a straight line under the… | NEET 1997 (AIPMT)

Q24NEET 1997 · AIPMTEasy

Work by a Constant Force

A body moves a distance of $10\text{ m}$ along a straight line under the action of a $5\text{ N}$ force. If the work done is $25\text{ J}$ , then angle between the force and direction of motion of the body is

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Answer: (a)

$W = Fs\cos\theta \Rightarrow 25 = 5 \times 10 \cos\theta$
$\cos\theta = \frac{1}{2} \Rightarrow \theta = 60^\circ$
So the answer is (a) $60^\circ$ .

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