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MHT CET 2026 (20 May, Shift 1) · Equations of Kinematics

Equations of Kinematics question from MHT CET 2026 (20 May, Shift 1)

Q2MHT CET 2026 · 20 MAY · SHIFT 1Medium

Equations of Kinematics

A body moving with uniform acceleration travel 1616 m in the third second of its motion and 2424 m in the fifth second of its motion. The velocity of the body in 1010 second is

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Answer: (b)

  1. Sn=u+a2(2n−1)S_n = u + \frac{a}{2}(2n - 1), so S5−S3=2a=24−16=8⇒a=4 m/s2S_5 - S_3 = 2a = 24 - 16 = 8 \Rightarrow a = 4\text{ m/s}^2.
  2. S3=u+42(5)=u+10=16⇒u=6 m/sS_3 = u + \frac{4}{2}(5) = u + 10 = 16 \Rightarrow u = 6\text{ m/s}
  3. v=u+at=6+4(10)=46 m/sv = u + at = 6 + 4(10) = 46\text{ m/s}
  4. So the answer is (b) 4646 m/s.
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