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MHT CET 2023 (13 May, Shift 1) · Periodic Motion & SHM Basics

Periodic Motion & SHM Basics question from MHT CET 2023 (13 May, Shift 1)

Q34MHT CET 2023 · 13 MAY · SHIFT 1Medium

Periodic Motion & SHM Basics

A body of mass $0.04\text{ kg}$ executes simple harmonic motion (SHM) about $x = 0$ under the influence of force $F$ as shown in graph. The period of oscillation is

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Answer: (b)

From the graph, $F = -kx$ with $k = \frac{8}{2} = 4\text{ N/m}$ .
$T = 2\pi\sqrt{\frac{m}{k}} = 2\pi\sqrt{\frac{0.04}{4}} = 2\pi(0.1)$
So the answer is (b) $0.2\pi\text{ s}$ .

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