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MHT CET 2026 (15 Apr, Shift 2) · Velocity & Acceleration in SHM

Velocity & Acceleration in SHM question from MHT CET 2026 (15 Apr, Shift 2)

Q8MHT CET 2026 · 15 APR · SHIFT 2Easy

Velocity & Acceleration in SHM

A body of mass 0.40.4 kg performs simple harmonic motion. It experiences a restoring force of 0.40.4 N when its displacement from the mean position is 4 cm. The force constant and magnitude of acceleration respectively are

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Answer: (b)

  1. k=Fx=0.40.04=10k = \frac{F}{x} = \frac{0.4}{0.04} = 10 N/m
  2. a=Fm=0.40.4=1 m/s2a = \frac{F}{m} = \frac{0.4}{0.4} = 1\ \text{m/s}^2
  3. So the answer is (b) 1010 N/m, 1 m/s21\ \text{m/s}^2.
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