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JEE Main 2023 (31 Jan, Shift 2) · Friction Basics

Friction Basics question from JEE Main 2023 (31 Jan, Shift 2)

Q8JEE Main 2023 · 31 JAN · SHIFT 2Easy

Friction Basics

A body of mass 10 kg10\text{ kg} is moving with an initial speed of 20 m/s20\text{ m/s}. The body stops after 5 s5\text{ s} due to friction between body and the floor. The value of the coefficient of friction is:

(Take acceleration due to gravity g=10 ms−2g = 10\text{ ms}^{-2})

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Answer: (d)

  1. Retardation a=205=4 m/s2a = \dfrac{20}{5} = 4\text{ m/s}^2
  2. a=μg⇒μ=410a = \mu g \Rightarrow \mu = \dfrac{4}{10}
  3. μ=0.4\mu = 0.4, so the answer is (d).
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