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JEE Main 2026 (4 Apr, Shift 1) · Power

Power question from JEE Main 2026 (4 Apr, Shift 1)

Q4JEE Main 2026 · 4 APR · SHIFT 1Medium

Power

A body of mass 2 kg begins to move under the influence of time dependent force F⃗=(2ti^+6t2j^) N\vec{F} = \left(2t\hat{i} + 6t^2\hat{j}\right)\text{ N}, where i^\hat{i} and j^\hat{j} are unit vectors along xx and y -axis respectively. The power produced by the force at t=2 st = 2\text{ s} is ______ W.

Numerical answer type. Work it out, then open the answer.

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Answer: 200

  1. a⃗=F⃗2=ti^+3t2j^\vec{a} = \dfrac{\vec{F}}{2} = t\hat{i} + 3t^2\hat{j}; from rest v⃗=t22i^+t3j^\vec{v} = \dfrac{t^2}{2}\hat{i} + t^3\hat{j}.
  2. At t=2t = 2: F⃗=4i^+24j^\vec{F} = 4\hat{i} + 24\hat{j}, v⃗=2i^+8j^\vec{v} = 2\hat{i} + 8\hat{j}.
  3. P=F⃗⋅v⃗=8+192=200 WP = \vec{F} \cdot \vec{v} = 8 + 192 = 200\text{ W}
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