A body of mass 2 kg is acted upon by two forces each of magnitude 1 N and inclined at 60° with each other. The acceleration of the body in m/s is [ cos 60° = 0.5 ] (a) √(0.75) (b) √(0.65) (c) √(0.20) (d) √(0.35)

Answer: (a). Resultant R = √(F² + F² + 2F²cos 60°) = √(1 + 1 + 1) = √(3) N a = R/m = √(3)/2 = √(3/4) = √(0.75) m/s² So the answer is (a) √(0.75).

A body of mass 2 kg is acted upon by two forces each of magnitude 1 N… | MHT CET 2020 (16 Oct, Shift 1)

Q26MHT CET 2020 · 16 OCT · SHIFT 1Easy

Inertia, First & Second Laws

A body of mass $2\text{ kg}$ is acted upon by two forces each of magnitude $1\text{ N}$ and inclined at $60^\circ$ with each other. The acceleration of the body in $\text{m/s}$ is [ $\cos 60^\circ = 0.5$ ]

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Answer: (a)

Resultant $R = \sqrt{F^2 + F^2 + 2F^2\cos 60^\circ} = \sqrt{1 + 1 + 1} = \sqrt{3}\text{ N}$
$a = \frac{R}{m} = \frac{\sqrt{3}}{2} = \sqrt{\frac{3}{4}} = \sqrt{0.75}\text{ m/s}^2$
So the answer is (a) $\sqrt{0.75}$ .

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Inertia, First & Second Laws question from MHT CET 2020 (16 Oct, Shift 1)

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