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JEE Main 2025 (8 Apr, Shift 2) · Inertia, First & Second Laws

Inertia, First & Second Laws question from JEE Main 2025 (8 Apr, Shift 2)

Q8JEE Main 2025 · 8 APR · SHIFT 2Medium

Inertia, First & Second Laws

A body of mass 2 kg moving with velocity of v⃗in=3i^+4j^\vec{v}_{in} = 3\hat{i} + 4\hat{j} ms−1^{-1} enters into a constant force field of 6N directed along positive z-axis. If the body remains in the field for a period of 53\frac{5}{3} seconds, then velocity of the body when it emerges from force field is.

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Answer: (d)

  1. a⃗=6k^2=3k^ m/s2\vec{a} = \frac{6\hat{k}}{2} = 3\hat{k}\text{ m/s}^2; it changes only the zz-component.
  2. Δv⃗=a⃗t=3×53k^=5k^\Delta\vec{v} = \vec{a}t = 3 \times \frac{5}{3}\hat{k} = 5\hat{k}
  3. v⃗=3i^+4j^+5k^\vec{v} = 3\hat{i} + 4\hat{j} + 5\hat{k}. So the answer is (d).
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