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JEE Main 2018 (15 Apr, Shift 2) · Friction on an Incline

Friction on an Incline question from JEE Main 2018 (15 Apr, Shift 2)

Q23JEE Main 2018 · 15 APR · SHIFT 2Medium

Friction on an Incline

A body of mass 2 kg slides down with an acceleration of 3 m/s2 on a rough inclined plane having a slope of 30∘30^\circ. The external force required to take the same body up the plane with the same acceleration will be: (g = 10 m/s2)

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Answer: (b)

  1. Sliding down: mgsin⁡30∘−f=ma⇒10−f=2×3⇒f=4 Nmg\sin 30^\circ - f = ma \Rightarrow 10 - f = 2 \times 3 \Rightarrow f = 4\text{ N}.
  2. Going up, friction acts down the slope: F−mgsin⁡30∘−f=maF - mg\sin 30^\circ - f = ma.
  3. F=10+4+6=20 NF = 10 + 4 + 6 = 20\text{ N}
  4. So the answer is (b) 20 N.
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