A body of mass 4 kg experiences two forces F₁ = 5i + 8j + 7k and F₂ = 3i - 4j - 3k. The acceleration acting on the body is: (a) 2i + j + k (b) 4i + 2j + 2k (c) -2i - j - k (d) 2i + 3j + 3k

Answer: (a). Net force F = F₁ + F₂ = 8i + 4j + 4k N a = F/m = (8i + 4j + 4k)/(4) = 2i + j + k So the answer is (a) 2i + j + k.

A body of mass 4 kg experiences two forces F₁ = 5i + 8j + 7k and F₂ =… | JEE Main 2024 (1 Feb, Shift 2)

Q11JEE Main 2024 · 1 FEB · SHIFT 2Easy

Inertia, First & Second Laws

A body of mass $4\text{ kg}$ experiences two forces $\vec{F}_1 = 5\hat{i} + 8\hat{j} + 7\hat{k}$ and $\vec{F}_2 = 3\hat{i} - 4\hat{j} - 3\hat{k}$ . The acceleration acting on the body is:

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Answer: (a)

Net force $\vec{F} = \vec{F}_1 + \vec{F}_2 = 8\hat{i} + 4\hat{j} + 4\hat{k}\text{ N}$
$\vec{a} = \frac{\vec{F}}{m} = \frac{8\hat{i} + 4\hat{j} + 4\hat{k}}{4} = 2\hat{i} + \hat{j} + \hat{k}$
So the answer is (a) $2\hat{i} + \hat{j} + \hat{k}$ .

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