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NEET 1989 (AIPMT) · Impulse & Momentum Conservation

Impulse & Momentum Conservation question from NEET 1989 (AIPMT)

Q29NEET 1989 · AIPMTMedium

Impulse & Momentum Conservation

A body of mass $5\text{ kg}$ explodes at rest into three fragments with masses in the ratio $1:1:3$ . The fragments with equal masses fly in mutually perpendicular directions with speeds of $21\text{ m/s}$ . The velocity of heaviest fragment in m/s will be

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Answer: (a)

Masses: $1$ kg, $1$ kg, $3$ kg. Total momentum stays zero.
Light fragments: $p = 1 \times 21 = 21$ each, perpendicular, resultant $= 21\sqrt{2}$ .
$3v = 21\sqrt{2} \Rightarrow v = 7\sqrt{2}$ m/s
So the answer is (a) $7\sqrt{2}$ .

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