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JEE Main 2024 (5 Apr, Shift 1) · Work by a Constant Force

Work by a Constant Force question from JEE Main 2024 (5 Apr, Shift 1)

Q8JEE Main 2024 · 5 APR · SHIFT 1Easy

Work by a Constant Force

A body of mass 50 kg50\text{ kg} is lifted to a height of 20 m20\text{ m} from the ground in the two different ways as shown in the figures. The ratio of work done against the gravity in both the respective cases, will be:

Figure

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Answer: (c)

  1. Work against gravity depends only on the vertical rise: W=mghW = mgh (gravity is conservative).
  2. Both cases: W=50×g×20W = 50 \times g \times 20, same value.
  3. So the answer is (c) 1:11 : 1.
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