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JEE Main 2023 (11 Apr, Shift 2) · Inertia, First & Second Laws

Inertia, First & Second Laws question from JEE Main 2023 (11 Apr, Shift 2)

Q16JEE Main 2023 · 11 APR · SHIFT 2Medium

Inertia, First & Second Laws

A body of mass 500 g500\text{ g} moves along xx-axis such that its velocity varies with displacement xx according to the relation v=10x m/sv = 10\sqrt{x}\text{ m/s} the force acting on the body is:-

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Answer: (c)

  1. a=vdvdx=10x×5x=50 m/s2a = v\frac{dv}{dx} = 10\sqrt{x} \times \frac{5}{\sqrt{x}} = 50\text{ m/s}^2
  2. F=ma=0.5×50=25 NF = ma = 0.5 \times 50 = 25\text{ N}
  3. So the answer is (c) 25 N.
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