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JEE Main 2004 (AIEEE) · Power

Power question from JEE Main 2004 (AIEEE)

Q48JEE Main 2004 · AIEEEEasy

Power

A body of mass ’m’,\text{'}m\text{'}, accelerates uniformly from rest to ’v1’\text{'}v_1\text{'} in time TT. The instantaneous power delivered to the body as a function of time is given by

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Answer: (b)

  1. a=v1Ta = \dfrac{v_1}{T}, so F=mv1TF = \dfrac{mv_1}{T} and v(t)=v1tTv(t) = \dfrac{v_1 t}{T}.
  2. P=F v(t)=mv12 tT2P = F\,v(t) = \dfrac{mv_1^2\,t}{T^2}
  3. So the answer is (b).
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