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MHT CET 2023 (12 May, Shift 2) · Critical Speed & Looping

Critical Speed & Looping question from MHT CET 2023 (12 May, Shift 2)

Q8MHT CET 2023 · 12 MAY · SHIFT 2Easy

Critical Speed & Looping

A body of mass ' $m$ ' attached at the end of a string is just completing the loop in a vertical circle. The apparent weight of the body at the lowest point in its path is ( $g$ = gravitational acceleration)

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Answer: (d)

Just completing: $v_{bottom}^2 = 5gr$
$T = mg + 5mg = 6mg$
So the answer is (d) $6\,mg$ .

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