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MHT CET 2026 (19 Apr, Shift 2) · Critical Speed & Looping

Critical Speed & Looping question from MHT CET 2026 (19 Apr, Shift 2)

Q1MHT CET 2026 · 19 APR · SHIFT 2Easy

Critical Speed & Looping

A body of mass 'm' attached at the end of a string is just completing the loop in a vertical circle. The apparent weight of the body at the lowest point in its path is

( $g$ = gravitational acceleration)

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Answer: (a)

Just completing the loop: $v_{top}^2 = gr \Rightarrow v_{bottom}^2 = 5gr$
At the lowest point: $T = mg + \frac{mv^2}{r} = mg + 5mg = 6mg$
Apparent weight = tension, so the answer is (a) $6\,mg$ .

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