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MHT CET 2019 (3 May, Shift 1) · Centripetal Acceleration & Force

Centripetal Acceleration & Force question from MHT CET 2019 (3 May, Shift 1)

Q44MHT CET 2019 · 3 MAY · SHIFT 1Easy

Centripetal Acceleration & Force

A body of mass $m$ is performing a UCM in a circle of radius $r$ with speed $v$ . The work done by the centripetal force in moving it through $\left(\frac{2}{3}\right)\text{rd}$ of the circular path is

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Answer: (a)

Centripetal force is along the radius; displacement at every instant is along the tangent.
$dW = F\,ds\cos 90^\circ = 0$ at every point.
So the work over any part of the circle is zero. The answer is (a) zero.

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