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NEET 2002 (AIPMT) · Gravitational Potential & Energy

Gravitational Potential & Energy question from NEET 2002 (AIPMT)

Q38NEET 2002 · AIPMTMedium

Gravitational Potential & Energy

A body of mass m is placed on earth's surface which is taken from earth surface to a height of h = 3R, then change in gravitational potential energy is

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Answer: (c)

$\Delta U = \frac{mgh}{1 + h/R}$
With $h = 3R$ : $\Delta U = \frac{3mgR}{1+3} = \frac{3}{4}mgR$
So the answer is (c) $\frac{3}{4}mgR$ .

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