A body of mass ' m ' is raised through a height above the earth's surface so that the increase in potential energy is mgR/5. The height to which the body is raised is ( R = radius of earth, g = acceleration due to gravity) (a) R (b) R/2 (c) R/4 (d) R/8

Answer: (c). Increase in PE: Δ U = (mgh)/(1 + h/R) (mgh)/(1+h/R) = mgR/5 ⇒ 5hR = R(R+h) 4h = R So the answer is (c) h = R/4.

A body of mass ' m ' is raised through a height above the earth's… | MHT CET 2023 (13 May, Shift 1)

Q12MHT CET 2023 · 13 MAY · SHIFT 1Medium

Gravitational Potential & Energy

A body of mass ' $m$ ' is raised through a height above the earth's surface so that the increase in potential energy is $\frac{mgR}{5}$ . The height to which the body is raised is ( $R =$ radius of earth, $g =$ acceleration due to gravity)

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Answer: (c)

Increase in PE: $\Delta U = \frac{mgh}{1 + h/R}$
$\frac{mgh}{1+h/R} = \frac{mgR}{5} \Rightarrow 5hR = R(R+h)$
$4h = R$
So the answer is (c) $h = \frac{R}{4}$ .

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Gravitational Potential & Energy question from MHT CET 2023 (13 May, Shift 1)

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