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MHT CET 2026 (19 May, Shift 1) · Escape Velocity

Escape Velocity question from MHT CET 2026 (19 May, Shift 1)

Q7MHT CET 2026 · 19 MAY · SHIFT 1Medium

Escape Velocity

A body of mass 'm' is raised to a height ' $10R$ ' from the surface of the earth, where 'R' is the radius of the earth. Suppose it is released now. The speed with which it will strike the surface of the earth is nearly

[ $g$ = acceleration due to gravity]

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Answer: (a)

Released at distance $11R$ from the centre; energy conservation: $\frac{1}{2}v^2 = GM\left(\frac{1}{R} - \frac{1}{11R}\right)$ .
With $GM = gR^2$ : $\frac{1}{2}v^2 = gR\cdot\frac{10}{11}$ .
$v = \sqrt{\frac{20gR}{11}}$ .
So the answer is (a) $\sqrt{\frac{20gR}{11}}$ .

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