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JEE Main 2023 (25 Jan, Shift 2) · Gravitational Potential & Energy

Gravitational Potential & Energy question from JEE Main 2023 (25 Jan, Shift 2)

Q9JEE Main 2023 · 25 JAN · SHIFT 2Easy

Gravitational Potential & Energy

A body of mass m is taken from earth surface to the height h equal to twice the radius of earth (R ${}_e$ ), the increase in potential energy will be:

(g = acceleration due to gravity on the surface of Earth)

Show answer and solution

Answer: (d)

$\Delta U = \frac{mgh}{1+\frac{h}{R_e}}$
With $h = 2R_e$ : $\Delta U = \frac{2mgR_e}{3}$
So the answer is (d) $\frac{2}{3}mgR_e$ .

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