Physics Circle home Student Login

Home›Chapters›Gravitation PYQs›Gravitational Potential & Energy›Question 3

JEE Main 2026 (5 Apr, Shift 2) · Gravitational Potential & Energy

Gravitational Potential & Energy question from JEE Main 2026 (5 Apr, Shift 2)

Q3JEE Main 2026 · 5 APR · SHIFT 2Easy

Gravitational Potential & Energy

A body of mass mm is taken from the surface of earth to a height equal to twice the radius of earth (Re)(R_e). The increase in potential energy will be ______.

( gg is acceleration due to gravity at the surface of earth)

Show answer and solution

Answer: (d)

  1. ΔU=mgh1+hRe\Delta U = \frac{mgh}{1+\frac{h}{R_e}}
  2. With h=2Reh = 2R_e: ΔU=2mgRe3\Delta U = \frac{2mgR_e}{3}
  3. So the answer is (d) 23mgRe\frac{2}{3}mgR_e.
Report a mistake

More questions on Gravitational Potential & Energy