Student Login

Home›Chapters›Gravitation PYQs›Gravitational Potential & Energy›Question 30

NEET 2013 · Gravitational Potential & Energy

Gravitational Potential & Energy question from NEET 2013

Q30NEET 2013Easy

Gravitational Potential & Energy

A body of mass 'm' is taken from the earth's surface to the height equal to twice the radius (R) of the earth. The change in potential energy of body will be

Show answer and solution

Answer: (d)

$\Delta U = \frac{mgh}{1+\frac{h}{R}}$
With $h = 2R$ : $\Delta U = \frac{2mgR}{3}$
So the answer is (d) $\frac{2}{3}mgR$ .

Report a mistake

More questions on Gravitational Potential & Energy

Infinite number of bodies, each of mass 2 kg are situated on x-axis at distance 1 m, 2 m…NEET 2013
The gravitational field in a region is given by: E = (5 N/kg)i + (12 N/kg)j. If the…JEE Main 2013 (25 Apr, Shift 1)
A particle of mass M is situated at the centre of a spherical shell of same mass and…NEET 2011 (AIPMT, Mains)
Two bodies of masses m and 4m are placed at a distance r. The gravitational potential at…JEE Main 2011 (AIEEE)
A particle of mass M is situated at the centre of a spherical shell of same mass and…NEET 2010 (AIPMT, Prelims)
A particle of mass 10 g is kept on the surface of a uniform sphere of mass 100 kg and…JEE Main 2005 (AIEEE)
If g is the acceleration due to gravity on the earth's surface, the gain in the potential…JEE Main 2004 (AIEEE)
A body of mass m is placed on earth's surface which is taken from earth surface to a…NEET 2002 (AIPMT)