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MHT CET 2023 (11 May, Shift 1) · Escape Velocity

Escape Velocity question from MHT CET 2023 (11 May, Shift 1)

Q34MHT CET 2023 · 11 MAY · SHIFT 1Medium

Escape Velocity

A body of mass ' $m$ ' kg starts falling from a distance 3R above earth's surface. When it reaches a distance ' $R$ ' above the surface of the earth of radius ' $R$ ' and Mass ' $M$ ', then its kinetic energy is

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Answer: (d)

Start: $3R$ above surface, i.e. $4R$ from centre; end: $2R$ from centre.
$K = GMm\left(\frac{1}{2R} - \frac{1}{4R}\right)$ .
$K = \frac{GMm}{4R}$ .
So the answer is (d) $\frac{1}{4}\frac{GMm}{R}$ .

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