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MHT CET 2024 (15 May, Shift 2) · Rolling Motion

Rolling Motion question from MHT CET 2024 (15 May, Shift 2)

Q29MHT CET 2024 · 15 MAY · SHIFT 2Medium

Rolling Motion

A body of mass mm slides down an incline and reaches the bottom with a velocity V. If the same mass were in the form of a disc which rolls down this incline, the velocity of the disc at bottom would have been

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Answer: (d)

  1. Sliding: V2=2ghV^2 = 2gh.
  2. Rolling disc: mgh=12mv2(1+12)⇒v2=43ghmgh = \frac{1}{2}mv^2\left(1 + \frac{1}{2}\right) \Rightarrow v^2 = \frac{4}{3}gh.
  3. v2V2=23⇒v=V23\dfrac{v^2}{V^2} = \dfrac{2}{3} \Rightarrow v = V\sqrt{\frac{2}{3}}.
  4. So the answer is (d).
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