A body of weight 200 N is suspended from a tree branch through a chain of mass 10 kg. The branch pulls the chain by a force equal to (if g = 10 m/s²): (a) 300 N (b) 100 N (c) 150 N (d) 200 N

Answer: (a). The branch supports the chain and the body hanging from it. F = 200 + 10 × 10 = 300 N So the answer is (a) 300 N.

A body of weight 200 N is suspended from a tree branch through a… | JEE Main 2024 (6 Apr, Shift 2)

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Equilibrium, Third Law & Frames

A body of weight $200\text{ N}$ is suspended from a tree branch through a chain of mass $10\text{ kg}$ . The branch pulls the chain by a force equal to (if $g = 10\text{ m/s}^2$ ):

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Answer: (a)

The branch supports the chain and the body hanging from it.
$F = 200 + 10 \times 10 = 300\text{ N}$
So the answer is (a) 300 N.

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