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MHT CET 2021 (22 Sep, Shift 1) · Centripetal Acceleration & Force

Centripetal Acceleration & Force question from MHT CET 2021 (22 Sep, Shift 1)

Q33MHT CET 2021 · 22 SEP · SHIFT 1Easy

Centripetal Acceleration & Force

A body performing uniform circular motion of radius 'R' has frequency 'n'. It centripetal acceleration is

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Answer: (b)

  1. Centripetal acceleration a=ω2Ra = \omega^2 R with ω=2πn\omega = 2\pi n.
  2. a=(2πn)2R=4π2n2Ra = (2\pi n)^2 R = 4\pi^2 n^2 R
  3. So the answer is (b) 4π2n2R4\pi^2 n^2 R.
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