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MHT CET 2024 (16 May, Shift 2) · Centripetal Acceleration & Force

Centripetal Acceleration & Force question from MHT CET 2024 (16 May, Shift 2)

Q9MHT CET 2024 · 16 MAY · SHIFT 2Easy

Centripetal Acceleration & Force

A body performing uniform circular motion of radius ' $R$ ' has frequency ' $n$ '. Its centripetal acceleration per unit radius is proportional to $(n)^x$ . The value of $x$ is

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Answer: (b)

$a = \omega^2 R = 4\pi^2 n^2 R$ .
$\frac{a}{R} = 4\pi^2 n^2 \propto n^2$ , so $x = 2$ .
So the answer is (b) 2.

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