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MHT CET 2020 (16 Oct, Shift 2) · Rolling Motion

Rolling Motion question from MHT CET 2020 (16 Oct, Shift 2)

Q64MHT CET 2020 · 16 OCT · SHIFT 2Medium

Rolling Motion

A body slides down a smooth inclined plane having angle $\theta$ and reaches the bottom with velocity $v$ . If a body is a sphere, then its linear velocity at the bottom of the plane is

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Answer: (b)

Sliding: $v^2 = 2gh$ .
Rolling sphere: $mgh = \frac{7}{10}mv'^2 \Rightarrow v'^2 = \frac{10}{7}gh$ .
$v' = \sqrt{\frac{5}{7}}\,v$ .
So the answer is (b).

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