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MHT CET 2025 (19 Apr, Shift 2) · Rolling Motion

Rolling Motion question from MHT CET 2025 (19 Apr, Shift 2)

Q15MHT CET 2025 · 19 APR · SHIFT 2Medium

Rolling Motion

A body slides down a smooth inclined plane of inclination θ\theta and reaches the bottom with velocity V. If the same body is a ring which rolls down the same inclined plane then linear velocity at the bottom of plane is

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Answer: (a)

  1. Sliding: V2=2ghV^2 = 2gh.
  2. Rolling ring (k=Rk = R): mgh=mv2⇒v2=ghmgh = mv^2 \Rightarrow v^2 = gh.
  3. v=V2v = \dfrac{V}{\sqrt{2}}.
  4. So the answer is (a).
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