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MHT CET 2026 (13 Apr, Shift 1) · Rolling Motion

Rolling Motion question from MHT CET 2026 (13 Apr, Shift 1)

Q6MHT CET 2026 · 13 APR · SHIFT 1Medium

Rolling Motion

A body slides down a smooth inclined plane of inclination $\theta$ and reaches the bottom with velocity 'V'. If the same body is a ring which rolls down the same inclined plane then linear velocity at the bottom of the plane is

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Answer: (a)

Sliding: $V^2 = 2gh$ .
Rolling ring ( $k = R$ ): $mgh = \frac{1}{2}mv^2(1+1) \Rightarrow v^2 = gh$ .
$v = \sqrt{gh} = \dfrac{V}{\sqrt{2}}$ .
So the answer is (a).

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