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MHT CET 2025 (21 Apr, Shift 2) · Equations of Kinematics

Equations of Kinematics question from MHT CET 2025 (21 Apr, Shift 2)

Q5MHT CET 2025 · 21 APR · SHIFT 2Medium

Equations of Kinematics

A body starts from rest and moves with a uniform acceleration. The ratio of the distance covered by the body in the nnth second of its motion to the total distance travelled in n second is

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Answer: (b)

  1. From rest: Sn=a2(2n−1)S_n = \frac{a}{2}(2n - 1) and S=12an2S = \frac{1}{2}an^2.
  2. SnS=2n−1n2=2n−1n2\frac{S_n}{S} = \frac{2n - 1}{n^2} = \frac{2}{n} - \frac{1}{n^2}
  3. So the answer is (b) 2n−1n2\frac{2}{n} - \frac{1}{n^2}.
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