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MHT CET 2024 (10 May, Shift 2) · Escape Velocity

Escape Velocity question from MHT CET 2024 (10 May, Shift 2)

Q23MHT CET 2024 · 10 MAY · SHIFT 2Medium

Escape Velocity

A body starts from rest from a distance $R_0$ from the centre of the earth. The velocity acquired by the body when it reaches the surface of the earth will be ( $R =$ radius of earth, $M =$ mass of earth)

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Answer: (b)

Loss of PE = gain of KE: $\frac{1}{2}mv^2 = GMm\left(\frac{1}{R} - \frac{1}{R_0}\right)$ .
$v = \sqrt{2GM\left(\frac{1}{R} - \frac{1}{R_0}\right)}$ .
So the answer is (b).

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