A body travelling with uniform acceleration crosses two points A and B with velocities 20 m/s and 30 m/s respectively. The speed of the body at mid point of A and B is (nearly) (a) 25 m/s (b) 25.5 m/s (c) 24 m/s (d) 10√(6) m/s

Answer: (b). For uniform acceleration, speed at the midpoint: vm = √((vA² + vB²)/(2)) (from v² = u² + 2as over each half). vm = √((400 + 900)/(2)) = √(650) vm ≈ 25.5 m/s. So the answer is (b).

A body travelling with uniform acceleration crosses two points A and… | MHT CET 2024 (16 May, Shift 2)

Q6MHT CET 2024 · 16 MAY · SHIFT 2Easy

Equations of Kinematics

A body travelling with uniform acceleration crosses two points A and B with velocities $20\text{ m/s}$ and $30\text{ m/s}$ respectively. The speed of the body at mid point of A and B is (nearly)

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Answer: (b)

For uniform acceleration, speed at the midpoint: $v_m = \sqrt{\frac{v_A^2 + v_B^2}{2}}$ (from $v^2 = u^2 + 2as$ over each half).
$v_m = \sqrt{\frac{400 + 900}{2}} = \sqrt{650}$
$v_m \approx 25.5\text{ m/s}$ . So the answer is (b).

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