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MHT CET 2023 (9 May, Shift 1) · Acceleration Due to Gravity

Acceleration Due to Gravity question from MHT CET 2023 (9 May, Shift 1)

Q58MHT CET 2023 · 9 MAY · SHIFT 1Easy

Acceleration Due to Gravity

A body weighs 300 N300\text{ N} on the surface of the earth. How much will it weigh at a distance R2\frac{R}{2} below the surface of earth? ( R→R \rightarrow Radius of earth)

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Answer: (d)

  1. Wd=W(1−dR)W_d = W\left(1 - \frac{d}{R}\right) with d=R2d = \frac{R}{2}.
  2. Wd=300×12=150 NW_d = 300 \times \frac{1}{2} = 150\ \text{N}
  3. So the answer is (d) 150 N150\ \text{N}.
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