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MHT CET 2025 (26 Apr, Shift 1) · Acceleration Due to Gravity

Acceleration Due to Gravity question from MHT CET 2025 (26 Apr, Shift 1)

Q16MHT CET 2025 · 26 APR · SHIFT 1Easy

Acceleration Due to Gravity

A body weighs 45 N on the surface of the earth. The gravitational force on a body due to earth at a height equal to half the radius of earth will be

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Answer: (a)

  1. Wh=W(1+h/R)2W_h = \frac{W}{(1 + h/R)^2} with h=R2h = \frac{R}{2}.
  2. Wh=45(3/2)2=45×49W_h = \frac{45}{(3/2)^2} = 45 \times \frac{4}{9}
  3. Wh=20 NW_h = 20\ \text{N}
  4. So the answer is (a) 20 N.
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