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MHT CET 2022 (11 Aug, Shift 2) · Acceleration Due to Gravity

Acceleration Due to Gravity question from MHT CET 2022 (11 Aug, Shift 2)

Q77MHT CET 2022 · 11 AUG · SHIFT 2Easy

Acceleration Due to Gravity

A body weighs $500\text{ N}$ on the surface of the earth. At what distance below the surface of the earth it weighs $250\text{ N}$ ? (Radius of earth, $R = 6400\text{ km}$ )

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Answer: (d)

$W_d = W\left(1 - \frac{d}{R}\right)$ , so $\frac{250}{500} = 1 - \frac{d}{R}$ .
$\frac{d}{R} = \frac{1}{2} \Rightarrow d = \frac{6400}{2}$
$d = 3200\ \text{km}$
So the answer is (d) 3200 km.

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