A bomb is dropped by an aeroplane flying horizontally with a velocity… | MHT CET 2021 (21 Sep, Shift 1)

Q6MHT CET 2021 · 21 SEP · SHIFT 1Easy

Horizontal Projectile & Inclined Plane

A bomb is dropped by an aeroplane flying horizontally with a velocity $200\text{ km/hr}$ and at a height of $980\text{ m}$ . At the time of dropping a bomb, the distance of the aeroplane from the target on the ground to hit directly is $\left(g = 9.8\text{ m/s}^{2}\right)$

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Answer: (c)

$v = 200\text{ km/h} = 200\times\frac{5}{18} = \frac{500}{9}\text{ m/s}$
Fall time $t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2\times 980}{9.8}} = \sqrt{200} = 10\sqrt{2}\text{ s}$
Horizontal distance $x = vt = \frac{500}{9}\times 10\sqrt{2} = \frac{5000\sqrt{2}}{9} = \frac{10^4}{9\sqrt{2}}\text{ m}$
So the answer is (c).

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Horizontal Projectile & Inclined Plane question from MHT CET 2021 (21 Sep, Shift 1)

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