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JEE Main 2016 (10 Apr, Shift 1) · Bulk Modulus & Compressibility

Bulk Modulus & Compressibility question from JEE Main 2016 (10 Apr, Shift 1)

Q20JEE Main 2016 · 10 APR · SHIFT 1Difficult

Bulk Modulus & Compressibility

A bottle has an opening of radius a and length b. A cork of length b and radius (a + Δ\Deltaa) where (Δ\Deltaa < < a) is compressed to fit into the opening completely (See figure). If the bulk modulus of cork is B and frictional coefficient between the bottle and cork is μ\mu then the force needed to push the cork into the bottle is:

Figure

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Answer: (d)

  1. Only the radius changes (length bb fixed): V=πr2b⇒ΔVV=2ΔaaV = \pi r^2 b \Rightarrow \frac{\Delta V}{V} = \frac{2\Delta a}{a}.
  2. Pressure on the cork: P=B ΔVV=2BΔaaP = B\,\frac{\Delta V}{V} = \frac{2B\Delta a}{a}
  3. Normal force on the curved surface: N=P×2πab=4πBb ΔaN = P\times2\pi a b = 4\pi B b\,\Delta a
  4. Force needed = friction =μN=(4πμBb) Δa= \mu N = (4\pi\mu B b)\,\Delta a
  5. So the answer is (d).
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