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NEET 2026 · Friction Basics

Friction Basics question from NEET 2026

Q1NEET 2026Easy

Friction Basics

A box of mass 15 kg is kept on the floor of a stationary trolley. The coefficient of static friction between the box and the trolley is 0.12. Keeping the box in stationary state over the trolley, the maximum acceleration with which the trolley can be moved horizontally in ms−2\text{ms}^{-2} is: (g=10 m/s2)(g = 10\text{ m/s}^{2})

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Answer: (d)

  1. Static friction is the only horizontal force on the box: ma≤μsmgma \le \mu_s mg.
  2. amax=μsg=0.12×10a_{max} = \mu_s g = 0.12 \times 10
  3. amax=1.2 m s−2a_{max} = 1.2\text{ m s}^{-2}, so the answer is (d).
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