A box of mass 5 kg is pulled by a cord, up along a frictionless plane inclined at 30° with the horizontal. The tension in the cord is 30 N. The acceleration of the box is (Take g = 10 m s⁻²) (a) 2 m s⁻² (b) Zero (c) 0.1 m s⁻² (d) 1 m s⁻²

Answer: (d). Along the incline: T - mgsin 30° = ma. 30 - 5 × 10 × 1/2 = 5a ⇒ 5 = 5a a = 1 m s⁻², so the answer is (d).

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Connected Bodies & Pulleys

A box of mass $5\text{ kg}$ is pulled by a cord, up along a frictionless plane inclined at $30^\circ$ with the horizontal. The tension in the cord is $30\text{ N}$ . The acceleration of the box is (Take $g = 10\text{ m s}^{-2}$ )

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Answer: (d)

Along the incline: $T - mg\sin 30^\circ = ma$ .
$30 - 5 \times 10 \times \frac{1}{2} = 5a \Rightarrow 5 = 5a$
$a = 1\text{ m s}^{-2}$ , so the answer is (d).

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