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JEE Main 2026 (24 Jan, Shift 1) · Time of Flight, Maximum Height & Range

Time of Flight, Maximum Height & Range question from JEE Main 2026 (24 Jan, Shift 1)

Q5JEE Main 2026 · 24 JAN · SHIFT 1Medium

Time of Flight, Maximum Height & Range

A boy throws a ball into air at 45∘45^\circ from the horizontal to land it on a roof of a building of height HH. If the ball attains maximum height in 2 s and lands on the building in 3 s after launch, then value of HH is ______ m.

(g=10 m/s2)\left(g = 10\text{ m/s}^{2}\right)

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Answer: (d)

  1. Time to reach maximum height t=usin⁡θg=2 st = \frac{u\sin\theta}{g} = 2\text{ s}, so usin⁡45∘=20 m/su\sin 45^\circ = 20\text{ m/s}.
  2. Height after 3 s3\text{ s}: y=(usin⁡θ)t−12gt2=20(3)−5(9)y = (u\sin\theta)t - \frac{1}{2}gt^2 = 20(3) - 5(9)
  3. H=60−45=15 mH = 60 - 45 = 15\text{ m}
  4. So the answer is (d) 15.
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