A boy throws a ball vertically upwards from a bridge with velocity 5 m/s. It strikes water surface after 2 s. The height of the bridge is (Take g = 10 m/s²) (a) 20 m (b) 15 m (c) 12 m (d) 10 m

Answer: (d). Take upward as positive: s = ut - 1/2gt² s = 5 × 2 - 1/2 × 10 × 2² = 10 - 20 = -10 m The water is 10 m below the bridge. So the answer is (d) 10 m.

A boy throws a ball vertically upwards from a bridge with velocity 5… | MHT CET 2025 (26 Apr, Shift 1)

Q10MHT CET 2025 · 26 APR · SHIFT 1Easy

Motion Under Gravity

A boy throws a ball vertically upwards from a bridge with velocity $5\text{ m/s}$ . It strikes water surface after 2 s. The height of the bridge is (Take $g = 10\text{ m/s}^2$ )

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Answer: (d)

Take upward as positive: $s = ut - \frac{1}{2}gt^2$
$s = 5 \times 2 - \frac{1}{2} \times 10 \times 2^2 = 10 - 20 = -10$ m
The water is 10 m below the bridge. So the answer is (d) 10 m.

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