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MHT CET 2024 (11 May, Shift 1) · Equations of Kinematics

Equations of Kinematics question from MHT CET 2024 (11 May, Shift 1)

Q12MHT CET 2024 · 11 MAY · SHIFT 1Medium

Equations of Kinematics

A bullet is fired on a target with velocity V. Its velocity decreases from V to $V/2$ . When it penetrates 30 cm in a target. Through what thickness it will penetrate further in the target before coming to rest?

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Answer: (c)

Constant retardation: $v^2 = u^2 - 2as$ , so the drop in $v^2$ is proportional to distance.
First 30 cm: $V^2 - \frac{V^2}{4} = \frac{3V^2}{4} = 2a(30)$
Rest of the way: $\frac{V^2}{4} = 2a(x)$
Dividing: $\frac{x}{30} = \frac{1}{3} \Rightarrow x = 10\text{ cm}$
So the answer is (c) 10 cm.

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