A bullet of mass 0.1 kg is fired on a wooden block to pierce through… | JEE Main 2021 (18 Mar, Shift 1)

Q20JEE Main 2021 · 18 MAR · SHIFT 1Easy

Inertia, First & Second Laws

A bullet of mass 0.1 kg is fired on a wooden block to pierce through it, but it stops after moving a distance of 50 cm into it. If the velocity of bullet before hitting the wood is 10 m/s and it slows down with uniform deceleration, then the magnitude of effective retarding force on the bullet is 'x' N. The value of 'x' to the nearest integer is __________.

Numerical answer type. Work it out, then open the answer.

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Answer: 10

$v^2 = u^2 - 2as \Rightarrow 0 = 10^2 - 2a(0.5) \Rightarrow a = 100\text{ m/s}^2$
$F = ma = 0.1 \times 100 = 10\text{ N}$
So $x = 10$ N.

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