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JEE Main 2023 (8 Apr, Shift 2) · Collisions

Collisions question from JEE Main 2023 (8 Apr, Shift 2)

Q4JEE Main 2023 · 8 APR · SHIFT 2Medium

Collisions

A bullet of mass 0.1 kg0.1\text{ kg} moving horizontally with speed 400 m s−1400\text{ m s}^{-1} hits a wooden block of mass 3.9 kg3.9\text{ kg} kept on a horizontal rough surface. The bullet gets embedded into the block and moves 20 m20\text{ m} before coming to rest. The coefficient of friction between the block and the surface is __________. (Given g=10 m/s2g = 10\text{ m/s}^2)

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Answer: (b)

  1. Momentum: 0.1×400=4 v⇒v=10 m/s0.1 \times 400 = 4\,v \Rightarrow v = 10\text{ m/s}
  2. Friction stops it: v2=2μgs⇒100=2μ(10)(20)v^2 = 2\mu g s \Rightarrow 100 = 2\mu(10)(20)
  3. μ=100400=0.25\mu = \frac{100}{400} = 0.25
  4. So the answer is (b) 0.25.
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