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JEE Main 2022 (30 Jul, Shift 2) · Impulse & Momentum Conservation

Impulse & Momentum Conservation question from JEE Main 2022 (30 Jul, Shift 2)

Q14JEE Main 2022 · 30 JUL · SHIFT 2Easy

Impulse & Momentum Conservation

A bullet of mass 1010 gram is fired with velocity of 100 m/s100\text{ m/s} from the gun of mass 1 kg1\text{ kg}. Recoil speed of the gun is:

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Answer: (a)

  1. Momentum is conserved: mbvb=MgVgm_b v_b = M_g V_g.
  2. 0.01×100=1×Vg0.01 \times 100 = 1 \times V_g
  3. Vg=1 m/sV_g = 1\text{ m/s}
  4. So the answer is (a) 1 m/s.
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